Lt’s see the relations below and find which one is true and which one is false:
Consider LHS,
= RHS
So, the given relation is true.
Let's simplify:
Given
Multiply and divide the first part with ‘2c’, and the second part with ‘3b’, we get
Hence
Lt’s see the relations below and find which one is true and which one is false:
So, the given statement is false.
Let's simplify:
Given
Multiply and divide the second part with ‘m’, we get
Hence
Lt’s see the relations below and find which one is true and which one is false:
Consider LHS,
Multiplying and dividing by (-1), we get,
= RHS
So, the given relation is true.
Let's simplify:
Given
Multiply and divide the first part with ‘(a + b)’, we get
We can (a + b)2 in simplified form as (a + b)2 = a2 + 2ab + b2, we get
Or
Hence
Lt’s see the relations below and find which one is true and which one is false:
(iv)
Consider LHS,
So, the given relation is false.
Let's simplify:
Given
Multiply and divide the first part with ‘(x - y)’ and the second part with ‘(x + y)’, we get
But we know (x + y)(x - y) = (x2 - y2), so the above expression becomes,
Hence
Let’s express the following algebraic fractions in the reduced from:
Cancelling 7b4, we get,
Let’s express the following algebraic fractions in the reduced from:
Cancelling 3a4b2, we get,
Let’s express the following algebraic fractions in the reduced from:
Let’s express the following algebraic fractions in the reduced from:
(iv)
Cancelling same terms from numerator and denominator.
Let’s express the following algebraic fractions in the reduced from:
Cancelling same terms from numerator and denominator.
Let’s express the following algebraic fractions in the reduced from:
Cancelling same terms from numerator and denominator, we get
Let’s express the following algebraic fractions in the reduced from:
Cancelling same terms from numerator and denominator, we get
Let’s simplify the following algebraic expressions.
Multiplying and dividing first term by c, second term by a and third term by b respectively, we get,
Let’s simplify the following algebraic expressions.
Let’s simplify the following algebraic expressions.
Let’s simplify the following algebraic expressions.
Cancelling same terms from numerator and denominator we get,
Let’s simplify the following algebraic expressions.
Multiplying first term by (x – 3), second term by (x – 1), third term by (x – 2), respectively, we get,
Let’s simplify the following algebraic expressions.
Let’s simplify the following algebraic expressions.
Cancelling same terms from denominator we get,
= a
Let’s simplify the following algebraic expressions.
Multiplying and dividing all three terms with (-1).
Also, multiplying and dividing first term with (b – c), second term with (c – a), third term with (a – b).
= 0
Let’s simplify the following algebraic expressions.
Multiplying and dividing all three terms with (-1).
Also, multiplying and dividing first term with (b – c), second term with (c – a), third term with (a – b).
= 0
Let’s simplify the following algebraic expressions.
= x
Let’s simplify the following algebraic expressions.
= 1
Let’s simplify the following algebraic expressions.
Multiplying and dividing first term by a, second term by b and third term by c, we get
= 6
Let’s simplify the following algebraic expressions.
Multiplying and dividing all three terms with (-1).
Also, multiplying and dividing first term with (y – z), second term with (z – x), third term with (x – y).
= 0
Lets express in reduced from:
Given
Cancelling the like terms, we get
Cancelling the like terms, we get
Combining the like terms, we get
Hence the given expression in reduced form is as shown below,
Lets express the algebraic expression given below in reduced from:
Given
By cancelling the like term ‘c2’, we get
But we know, , so the above expression becomes
By cancelling the like terms, we get
Hence
Lets express the algebraic expression given below in reduced from:
Given
Bringing out the common variable out, we get
Now cancelling the like terms, we get
Hence
Lets express the algebraic expression given below in reduced from:
Given
But we know, , so the above expression becomes
But we know (x2 - y2) = (x + y)(x - y), so the above expression becomes,
Now cancelling the like terms, we get
⇒ = (p + q)(x - y)
By opening the brackets, we get
⇒ = p(x - y) + q(x - y)
⇒ = px - py + qx - qy
Hence