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Multiplication And Division Of Polynomials

Class 8th Mathematics West Bengal Board Solution
Lets Do 4.1
  1. (x2 – 13x + 22) by (x – 11) Let's divide by arranging in decreasing Powers of…
  2. (a2 – 5a + 6) by (a – 2) Let's divide by arranging in decreasing Powers of variables.…
  3. (2a3 – 7a2 – a + 2) by (a2 – 3a – 2) Let's divide by arranging in decreasing Powers of…
  4. (4a2 – 9b2) by (2a + 3b) Let's divide by arranging in decreasing Powers of variables.…
  5. Let's find divisor, quotient and remainder of the expression in the colour cards given…
Lets Do 4.1
Question 1.

Let's divide by arranging in decreasing Powers of variables.

(x2 – 13x + 22) by (x – 11)
Answer:



Question 2.

Let's divide by arranging in decreasing Powers of variables.

(a2 – 5a + 6) by (a – 2)
Answer:



Question 3.

Let's divide by arranging in decreasing Powers of variables.

(2a3 – 7a2 – a + 2) by (a2 – 3a – 2)
Answer:


Quotient = 2a – 1 & Remainder = 0
Question 4.

Let's divide by arranging in decreasing Powers of variables.

(4a2 – 9b2) by (2a + 3b)
Answer:


Quotient = 2a – 3b & Remainder = 0
Question 5.

Let's find divisor, quotient and remainder of the expression in the colour cards given below


Let's find divisor and remainder of the expression in red cards.
Answer:

Red Coloured Card –


Dividend = Divisor Quotient + Remainder


6x3y – x2y2 – 7xy3 + 12y4 = Divisor 2x + 3y +Remainder



Divisor = & Remainder = 4


Blue Coloured Card –


Dividend = Divisor Quotient + Remainder


12x4 + 5x3 – 33x2 – 3x + 16 = 4x2 – x – 5 Quotient +Remainder



Quotient = & Remainder = 3x – 4


Green Coloured Card –


x3 + px2 + qx + x = Divisor + Remainder


x3 + px2 + qx + x= Divisor + Remainder



Divisor = & Remainder = 4