i)
Ans:
ii)
⇒
⇒
Ans: ⇒
iii)
⇒
⇒
Ans: ⇒
Find the value of λ for which and are perpendicular, where
i. and
ii. and
iii. and
iv. and
i)
Since these two vectors are perpendicular,their dot product is zero.
Ans:
ii)
Since these two vectors are perpendicular,their dot product is zero.
Ans: λ = 3
iii)
Since these two vectors are perpendicular,their dot product is zero.
Ans: λ = - 2
iv)
Since these two vectors are perpendicular,their dot product is zero.
Ans: λ = - 2
i. If and show that is perpendicular to
ii. If and then show that and are orthogonal.
i)
Now
= (4 × - 2) + (1 × 3) + ( - 1 × - 5) = - 8 + 3 + 5 = 0
Since the dot product of these two vectors is 0,the vector is perpendicular to
Hence,proved.
ii)
Now
= (6 × 4) + (2 × - 4) + ( - 8 × 2) = 24 - 8 - 16 = 0
Since the dot product of these two vectors is 0,the vector is perpendicular to
Hence,proved that and are orthogonal.
If and then find the value of λ so that and are orthogonal vectors.
(
Now
Since these two vectors are orthogonal,their dot product is zero.
⇒ (6 × - 4) + ( - 2 × 0) + ( (7 + λ) × (7 - λ)) = 0
⇒ - 24 + 0 + (49 - λ2) = 0
⇒ λ2 = 25
⇒ λ = ±5
Ans: λ = ±5
Show that the vectors
and
are mutually perpendicular unit vectors.
Let,
|| = || = || = 1
We have to show that :
L.H.S.
= R.H.S.
Hence,showed that vectors are mutually perpendicular unit vectors.
Let and
Find a vector which is perpendicular to both and and is such that
Let
the vector which is perpendicular to both and
⇒
⇒
Solving equations 1,2,3 simultaneously we get
p = 7,q = - 7,r = - 7
∴
Ans:
Let and
Find the projection of (i) on and (ii) on
|| =
|| =
Projection of
Projection of
Ans: i)
ii)
Find the projection of in the direction of
Let,
|| =
∴ The projection of
is:
Ans:10/3
Write the projection of vector along the vector
Let,
|| =
∴ The projection of
is:
Ans:1
i. Find the projection of on if and
ii. Write the projection of the vector on the vector
i)
|| =
Projection of on
=
=
ANS:8/7
ii) Sol:
Let,
|| =
∴ The projection of
is:
Ans: 0
Find the angle between the vectors and when
i. and
ii. and
iii. and
i) and
|| =
|| =
We know that ,
⇒
⇒ (3 + 4 + 3) = 14cosθ
⇒ cosθ = 10/14
⇒ cosθ = 5/7
⇒ θ = cos - 1(5/7)
Ans: θ = cos - 1(5/7)
ii) and
|| =
|| =
We know that ,
⇒
⇒ (6 - 2 + 8) = √336 cosθ
⇒ cosθ = 12/√336
⇒ cosθ = √(144/336)
⇒ θ = cos - 1√ (3/7)
Ans: θ = cos - 1√ (3/7)
iii. and
Ans:
|| =
|| =
We know that ,
⇒
⇒ ( - 1) = 2 cosθ
⇒ cosθ = - 1/2
⇒ θ = cos - 1 - 1/2
⇒ θ = 120⁰
Ans: θ = 120⁰
If and then calculate the angle between and
|| =
|| =
We know that ,
⇒
⇒ (35 - 4) = 50 cosθ
⇒ cosθ = 31/50
⇒ θ = cos - 1(31/50)
Ans: θ = cos - 1(31/50)
If is a unit vector such that find
If is a unit vector
⇒ || = 1
⇒
⇒ ||2 - ||2 = 8
⇒ ||2 = 8 + 1 = 9
⇒ || = 3
Ans: || = 3
Find the angles which the vector makes with the coordinate axes.
If we have a vector = a + b + c
then the angle with the x - axis =
the angle with the y - axis =
the angle with the z - axis =
Here, = 3 - 6 + 2
then the angle with the x - axis =
the angle with the y - axis =
the angle with the z - axis =
Ans:
Show that the vector is equally inclined to the coordinate axes.
If we have a vector = a + b + c
then the angle with the x - axis =
the angle with the y - axis =
the angle with the z - axis =
Here,
then the angle with the x - axis =
the angle with the y - axis =
the angle with the z - axis =
Now since,
∴ the vector is equally inclined to the coordinate axes.
Hence,proved.
Find a vector of magnitude making an angle π/4 with x - axis, π/2 with y - axis and an acute angle θ with z - axis.
|| = 5√2
l = cos α = cos π/4 = 1/√2
m = cos β = cos π/2 = 0
n = cosθ
we know that
l2 + m2 + n2 = 1
since the vector makes an acute angle with the z axis
∴
∴ = ||(l + m + n)
∴ = 5√2(1/√2 + 1/√2)
∴ = 5()
Ans: = 5()
Find the angle between and if and
|| =
|| =
We know that ,
⇒
⇒ ( - 5 + 5) = cosθ
⇒ cosθ = 0
⇒ θ = cos - 1(0) = π/2
Ans: θ = π/2
Express the vector as sum of two vectors such that one is parallel to the vector and the other is perpendicular to
∴
&
⇒
⇒
⇒
⇒ λ = - 1
∴
⇒
⇒
⇒
⇒
Ans:
Prove that where and
⇒
⇒
Which is not possible hence
If and find the angle between and
⇒
⇒
⇒
⇒
⇒
⇒
⇒
⇒
Ans:
Find the angle between and when
i. and
ii. and
i)
We know that ,
⇒
⇒
⇒ cosθ = √3/2
⇒ θ = cos - 1(√3/2) = 30⁰ =
Ans: θ = cos - 1(√3/2) = 30⁰ =
ii)
We know that ,
⇒
⇒
⇒ cosθ = - 1/2
⇒ θ = cos - 1( - 1/2) = 120⁰ =
Ans: θ = cos - 1( - 1/2) = 120⁰ =
If and find
We know that ,
⇒
⇒
⇒ cosθ = 4/6
⇒ cosθ = 2/3
⇒
⇒
⇒
⇒
Ans: √5
If and find and
().() = 8
⇒
⇒
⇒
⇒
⇒
⇒
Ans:
If and are unit vectors inclined at an angle θ then prove that:
i.
ii.
R.H.S:
)
⇒
⇒
⇒
⇒
⇒
⇒
⇒ = L.H.S
Hence, proved
ii)
R.H.S. =
⇒
⇒
⇒
⇒
⇒
⇒
⇒ tanθ/2 = L.H.S
Hence,proved.
The dot products of a vector with the vector and are 0, 5 and 8 respectively. Find the vector.
Let the unknown vector be:
∴
⇒ a + b - 3c = 0 …(1)
⇒ a + 3b - 2c = 5 …(2)
⇒ 2a + b + 4c = 8 …(3)
Solving equations 1 ,2,3, simultaneously we get:
a = 1,b = 2,c = 1
∴
Ans:
If and the coordinates of A are (0, - 2, - 1), find the coordinates of B.
⇒
⇒
⇒
∴ B(3, - 3,1)
Ans: B(3, - 3,1)
If A(2, 3, 4), B(5, 4, - 1), C(3, 6, 2) and D(1, 2, 0) be four points, show that is perpendicular to
Hence,
Find the value of λ for which the vectors and are perpendicular to each other.
Since these two vectors are perpendicular, their dot product is zero.
Ans:
Show that the vectors and form a right - angled triangle.
⇒
Hence, the triangle is a right angled triangle at c
Three vertices of a triangle are A(0, - 1, - 2), B(3, 1, 4) and C(5, 7, 1). Show that it is a right - angled triangle. Also, find its other two angles.
∴
∴
∴
Ans:45°,90°,45°
If the position vectors of the vertices
A, B and C of a ∆ABC be (1, 2, 3), ( - 1, 0, 0) and (0, 1, 2) respectively then find ∠ABC.
∴
Ans: = ∠ABC
If and are two unit vectors such that find
⇒
⇒ cosθ = 1/2
∴
⇒
⇒
Ans:
If and are two vectors such that then prove that vector is perpendicular to the vector
⇒
⇒
⇒
NOW,
⇒
⇒
Hence,
If and then express in the form where and
Let b1 = c and b2 = d
∴
&
⇒
⇒
⇒
⇒ λ = 5/10 = 1/2
∴
⇒
⇒
⇒ b1 + b2
⇒
Ans: