Find the general solution for each of the following differential equations.
Given Differential Equation :
………eq(1)
Formula :
i)
ii)
iii)
iv) General solution :
For the differential equation in the form of
The general solution is given by,
Where integrating factor,
Answer :
Equation (1) is of the form
Where, and Q = x2
Therefore, integrating factor is
………
= x ………
General solution is
………
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
The general solution is given by,
Where integrating factor,
Answer :
Given differential equation is
Dividing the above equation by x,
………eq(1)
Equation (1) is of the form
Where, and Q = x
Therefore, integrating factor is
………
………
= x2 ………
General solution is
………
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
The general solution is given by,
Where integrating factor,
Answer :
Given differential equation is
Dividing the above equation by 2x,
………eq(1)
Equation (1) is of the form
Where, and Q = 3x2
Therefore, integrating factor is
………
………
= √x………
General solution is
………
Dividing the above equation by √x
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv) General solution :
For the differential equation in the form of
The general solution is given by,
Where integrating factor,
Answer :
Given differential equation is
Dividing the above equation by x,
………eq(1)
Equation (1) is of the form
Where, and
Therefore, the integrating factor is
………
= x………
General solution is
………
Dividing the above equation by x
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
The general solution is given by,
Where integrating factor,
Answer :
Given differential equation is
Dividing the above equation by x,
………eq(1)
Equation (1) is of the form
Where, and Q = 2x2
Therefore, integrating factor is
………
………
………
General solution is
………
Multiplying above equation by x
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by x,
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
………
General solution is
………
Multiplying above equation by x,
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by (1+x2),
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
Let,
………
………
General solution is
………
Therefore, general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by (1 – x2),
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
Let (1 – x2) = f(x)
Therefore f’(x) = -2x
……eq(2)
………
………
General solution is
………from eq(2)
Multiplying above equation by ,
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by (1 – x2),
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
Let (1 – x2) = f(x)
Therefore f’(x) = -2x
………
………
General solution is
……eq(2)
Let
Put (1 – x2) = t
Substituting I in eq(2)
Multiplying above equation by ,
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v)
vi) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by (1 + x2),
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
Let (1 + x2) = f(x)
Therefore f’(x) = 2x
………
………
General solution is
………
Therefore general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
General solution is
………
Dividing above equation by ,
Therefore general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
General solution is
………
Dividing above equation by ,
Therefore general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
General solution is
………
Dividing above equation by ,
Therefore general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by x,
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
………
General solution is
………eq(2)
Let,
Let
………
Substituting I in eq(2),
Multiplying above equation by x,
Therefore general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
………
General solution is
………
Therefore general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v)
vi) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by (x.log x),
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
Let,
………
………
General solution is
………eq(2)
Let,
Let,
………
………
Substituting I in eq(2),
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v)
vi) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by x,
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
General solution is
………eq(2)
Let,
Let,
………
………
………
Substituting I in eq(2),
Multiplying above equation by 4,
Therefore general equation is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v)
vi)
vii) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by x,
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
………
General solution is
………eq(2)
Let,
Let,
………
………
………
Substituting I in eq(2),
Dividing above equation by x2,
Therefore general equation is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by (1+x),
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
………
General solution is
………
Multiplying above equation by (1+x),
Therefore general equation is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
Let,
………
………
………
General solution is
………
Dividing above equation by (1+x2)2,
Therefore general equation is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
………
General solution is
………
Multiplying above equation by x,
Therefore general equation is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
………
General solution is
………
Multiplying above equation by x,
Therefore general equation is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
General solution is
………
Dividing above equation by x,
Therefore general equation is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v)
vi) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
General solution is
………eq(2)
Let,
Let, u=sin x and v=e2x
………
………
Again, let u=cos x and v=e2x
………
………
Multiplying above equation by 4,
Substituting I in eq(2),
Dividing above equation by e2x,
Therefore general equation is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
General solution is
Let, f(x)=cos x => f ’(x) = -sin x
………
Dividing above equation by ex,
Therefore general equation is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by sec x,
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
General solution is
………eq(2)
Let,
Put sin x=t => cos x.dx=dt
………
………
………
Substituting I in eq(2),
Dividing above equation by e-sinx,
Therefore general equation is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by (1+x2),
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
Let, f(x) = (1+x2) => f ’ (x) = 2x
………
………
General solution is
………
Therefore, general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
v)
vi)
vii)
viii) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by sin x,
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
= sin x ………
General solution is
………eq(2)
Let,
Put sin x=t => cos x.dx=dt
………
Substituting I in eq(2),
Therefore, general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
= sin2 x ………
General solution is
………
Therefore, general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
vi)
vii)
viii)
ix)
x) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Dividing above equation by x,
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
………
General solution is
………
Multiplying above equation by x,
Therefore, general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v)
vi) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
………
General solution is
………
………
Multiplying above equation by 2,
where, C=2c
Therefore, general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v)
vi)
vii)
viii) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
General solution is
………eq(2)
Let,
Let, u=sin 2x & v=sin x
………
………
Again let, u=cos 2x & v=cos x
………
………
Substituting I in eq(2),
Therefore, general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
………
General solution is
………eq(2)
Let,
Put, cos x=t => -sin x dx = dt
………
Substituting I in eq(2),
Multiplying above equation by cos2x,
Therefore, general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v)
vi) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
= sin x ………
General solution is
………eq(2)
Let,
Let, u=x2 and v=cos x
………
………
Substituting I in eq(2),
Dividing above equation by sin x,
Therefore, general solution is
Find a particular solution satisfying the given condition for each of the following differential equations.
, given that 𝒴 =1 when 𝒳 =2
Given Differential Equation :
Formula :
i)
ii)
iii)
iv) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by x,
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
General solution is
………
Dividing above equation by x,
Therefore general equation is
For particular solution put y=1 and x=2 in above equation,
Therefore, particular solution is
Find a particular solution satisfying the given condition for each of the following differential equations.
, given that 𝒴 = 0 when 𝒳 =.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
= sin x ………
General solution is
………
Therefore general equation is
For particular solution put y=0 and in above equation,
Therefore, particular solution is
Find a particular solution satisfying the given condition for each of the following differential equations.
, given that 𝒴 = 0 when 𝒳 =0.
Given Differential Equation :
Formula :
i)
ii)
iii) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
General solution is
………eq(2)
Let,
Put, x2=t => 2x dx = dt
………
Substituting I in eq(2),
Therefore, general solution is
For particular solution put y=0 and x=0 in above equation,
Substituting c in general solution,
Multiplying above equation by
Therefore, particular solution is
Find a particular solution satisfying the given condition for each of the following differential equations.
, given that 𝒴 = 0, when 𝒳 = 0.
Given Differential Equation :
Formula :
i)
ii)
iii) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
General solution is
………
Therefore, general solution is
For particular solution put y=0 and x=0 in above equation,
Substituting c in general solution,
Therefore, particular solution is
Find a particular solution satisfying the given condition for each of the following differential equations.
, given that 𝒴 = 0 when 𝒳 = 0.
Given Differential Equation :
Formula :
i)
ii)
iii) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by (1+x2),
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
Let,
………
General solution is
………
Therefore, general solution is
For particular solution put y=0 and x=0 in above equation,
Substituting c in general solution,
Dividing above equation by (1+x2),
Therefore, particular solution is
Find a particular solution satisfying the given condition for each of the following differential equations.
, given that 𝒴 = 0 when 𝒳 = 1.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v)
vi)
vii)
viii) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
Dividing above equation by x,
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
………
General solution is
………eq(2)
Let,
Put, log x =t => x=et
Therefore, (1/x) dx = dt
Let, u=t and v=e-t
………
………
………
Substituting I in eq(2),
Multiplying above equation by x,
Therefore, general solution is
For particular solution put y=0 and x=1 in above equation,
………
Substituting c in general solution,
Therefore, particular solution is
Find a particular solution satisfying the given condition for each of the following differential equations.
, given that 𝒴 = 1 when 𝒳 = 0.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v)
vi) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
General solution is
………eq(2)
Let,
Let, u=x2 and v= tan x. sec x
………
………
Substituting I in eq(2),
Multiplying above equation by cos x,
Therefore, general solution is
For particular solution put y=1 and x=0 in above equation,
Substituting c in general solution,
Therefore, particular solution is
A curve passes through the origin and the slope of the tangent to the curve at any point (𝒳, ) is equal to the sum of the coordinates of the point. Find the equation of the curve.
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
The slope of the tangent to the curve
The slope of the tangent to the curve is equal to the sum of the coordinates of the point.
Therefore differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
General solution is
………eq(2)
Let,
Let, u=x and v= e-x
………
………
………
Substituting I in eq(2),
Dividing above equation by e-x,
Therefore, general solution is
The curve passes through origin , therefore the above equation satisfies for x=0 and y=0,
Substituting c in general solution,
Therefore, equation of the curve is
A curve passes through the point (0, 2) and the sum of the coordinates of any point on the curve exceeds the magnitude of the slope of the tangent to the curve at that point by 5. Find the equation of the curve.
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
The slope of the tangent to the curve
The sum of the coordinates of any point on the curve exceeds the magnitude of the slope of the tangent to the curve at the given point by 5.
Therefore differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
General solution is
………eq(2)
Let,
Let, u=x-5 and v= e-x
………
………
………
Substituting I in eq(2),
Dividing above equation by e-x,
Therefore, general solution is
The curve passes through point (0,2) , therefore the above equation satisfies for x=0 and y=2,
Substituting c in general solution,
Therefore, equation of the curve is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
………
General solution is
………
Multiplying above equation by y,
Therefore, general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
General solution is
………
Dividing above equation by y,
Therefore, general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
General solution is
………
Dividing above equation by y,
Therefore, general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
………
………
General solution is
………
Multiplying above equation by y,
Therefore, general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
General solution is
………eq(2)
Let,
Let, u=y and v= e-y
………
………
………
Substituting I in eq(2),
Therefore, general solution is
Find the general solution for each of the following differential equations.
Given Differential Equation :
Formula :
i)
ii)
iii)
iv)
v) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
General solution is
………eq(2)
Let,
Let, u=y+1 and v= e-y
………
………
………
Substituting I in eq(2),
Dividing above equation by e-y
Therefore, general solution is
Solve , given that 𝒳 = 0 when 𝒴 = 0.
Given Equation:
Re-arranging, we get,
Let 2 – ey = t
-eydy = dt
Therefore,
Integrating both sides, we get,
log t = log(x + 1) + C
log (2 – ey) = log (x + 1) + C
At x = 0, y = 0.
Therefore,
log(2) = log(1) + C
Therefore,
C = log 2
Now, we have,
log (2 – ey) – log (x + 1) – log 2 = 0
Solve , given that when 𝒴 =o, then 𝒳 = 0.
Given Differential Equation :
Formula :
i)
ii) General solution :
For the differential equation in the form of
General solution is given by,
Where, integrating factor,
Answer :
Given differential equation is
………eq(1)
Equation (1) is of the form
Where, and
Therefore, integrating factor is
………
General solution is
………
Putting x=0 and y=0
Therefore, general solution is
Mark (√) against the correct answer in the following:
The solution of the is
A.
B.
C.
D. None of these
Given,
On integrating on both sides, we get
Conclusion: Therefore, is the solution of
Mark (√) against the correct answer in the following:
The solution of the is
A.
B.
C.
D. None of these
Given,
On integrating on both sides, we get
Conclusion: Therefore, is the solution of
Mark (√) against the correct answer in the following:
The solution of the is
A.
B.
C.
D. None of these
Let,
On differentiating on both sides we get
Now we can write this equation as
On integrating on both sides, we get
Conclusion: Therefore, is the solution of
Mark (√) against the correct answer in the following:
The solution of the is
A.
B.
C.
D. None of these
Given xdy + ydx = 0
xdy = -ydx
On integrating on both sides we get,
-log y = log x + c
log x + log y = c
log xy = c
xy = C
Conclusion: Therefore xy = c is the solution of xdy + ydx = 0
Mark (√) against the correct answer in the following:
The solution of the is
A.
B.
C.
D. None of these
Given:
Separating the variables, we get,
Integrating both sides, we get,
log sec y = log x + log c
xcosy = c
Hence, A is the correct answer.
Mark (√) against the correct answer in the following:
The solution of the is.
A. (𝒴 +𝒳 )=C(1-𝒴𝒳)
B. (𝒴 – 𝒳 ) = C(1+𝒴𝒳)
C. 𝒴 = (1+𝒳 )C
D. None of these
Given
On integrating on both sides, we get
(since )
y-x = C(1+yx)
Conclusion: Therefore, y-x = C(1+yx) is the solution of
Mark (√) against the correct answer in the following:
The solution of the =1 - 𝒳 + 𝒴 – 𝒳𝒴 is
A. Log (1 + 𝒴) = 𝒳 - +C
B.
C.
D. None of these
On integrating on both sides, we get
Conclusion: Therefore, is the
solution of
Mark (√) against the correct answer in the following:
The solution of the is
A.
B.
C.
D. None of these
Given
On integrating on both sides, we get
Conclusion: Therefore, is the
solution of
Mark (√) against the correct answer in the following:
The solution of the is
A. 𝒴 + sin-1𝒴 = sin-1𝒳 + C
B. sin-1𝒴 – sin-1𝒳 = C
C. sin-1𝒴 + sin-1𝒳 = C
D. None of these
Given
On integrating on both sides, we get
( As )
Conclusion: Therefore, is the
solution of
Mark (√) against the correct answer in the following:
The solution of the is
A.
B.
C.
D. None of these
Given
On integrating on both sides, we get
Conclusion: Therefore, is the solution
of
Mark (√) against the correct answer in the following:
The solution of the is
A. 𝒴2 (𝒳 + 1) = C
B. 𝒴 (𝒳2 + 1) = C
C. 𝒳2 (𝒴 + 1) = C
D. None of these
Given
Let
On differentiating on both sides we get 2xdx = dt
On integrating on both sides, we get
yt = C
As
Conclusion: Therefore, is the solution of
Mark (√) against the correct answer in the following:
The solution of the DE cos 𝒳 (1 + cos 𝒴 ) 𝒹𝒳 – sin 𝒴 (1 + sin 𝒳) 𝒹𝒴 = 0 is
A. 1 + sin 𝒳 cos 𝒴 = C
B. (1 + sin 𝒳) (1 + cos 𝒴) = C
C. sin 𝒳 cos 𝒴 + cos 𝒳 = C
D. none of these
Given cos x (1+cos y) dx – sin y (1+sin x) dy = 0
Let 1+cos y = t and 1+sin x = u
On differentiating both equations, we get
-sin y dy = dt and cos x dx = du
Substitute this in the first equation
t du + u dt = 0
-log u = log t + C
log u + log t = C
log ut = C
ut = C
(1+sin x)(1+cos y) = C
Conclusion: Therefore, (1+sin x)(1+cos y) = C is the solution of cos x (1+cos y) dx – sin y (1+sin x) dy = 0
Mark (√) against the correct answer in the following:
the solution of the DE 𝒳 cos 𝒴 𝒹𝒴 = (𝒳e𝒳 log 𝒳 + e𝒳 ) 𝒹𝒳 is
A. sin 𝒴 = e𝒳 log 𝒳 +C
B. sin 𝒴 - e𝒳 log 𝒳 = C
C. sin 𝒴 = e𝒳 (log 𝒳) +C
D. none of these
Given
On integrating on both sides we get
Conclusion: Therefore, the solution of
Mark (√) against the correct answer in the following:
The solution of the DE + 𝒴 log 𝒴 cot 𝒳 = 0 is
A. cos 𝒳 log 𝒴 = C
B. sin 𝒳 log 𝒴 = C
C. log 𝒴 = C sin 𝒳
D. none of these
Given
Let log y = t
On differentiating we get
log t = -log (sin x) + C
log t + log(sin x) = C
log(tsin x) = C
tsin x = C
(log y)(sin x) = C
Conclusion: Therefore, (log y)(sin x) = C is the solution of
Mark (√) against the correct answer in the following:
the general solution of the DE (1 + 𝒳2) 𝒹𝒴 – 𝒳𝒴 𝒹𝒳 = 0 is
A. 𝒴 = C(1 + 𝒳2)
B. 𝒴2 = C(1 + 𝒳2)
C. = C
D. None of these
Given
Let
2x dx = dt
On integrating on both sides we get
2 log y = log t + C
Conclusion: Therefore, is the solution of
Mark (√) against the correct answer in the following:
The general solution of the =0 is
A. sin-1𝒳 + sin-1𝒴 = C
B.
C. tan-1𝒳 + tan-1𝒴 = C
D. None of these
Given
Let and
2y dy = dt and 2x dx = du
On integrating on both sides we get
Conclusion: Therefore, is the
solution of
Mark (√) against the correct answer in the following:
The general solution of the DE is
A.
B.
C.
D. None of these
Given
On integrating on both sides we get
Conclusion: Therefore, is the solution of
Mark (√) against the correct answer in the following:
The general solution of the is
A.
B.
C.
D. None of these
Given
Let x = sin t
dx = cos t dt
We know
On integrating on both sides we get
Sin 2t = 2 sin t cost
= 2x
Conclusion: Therefore, is the solution of
Mark (√) against the correct answer in the following:
The general solution of the DE is
A.
B.
C.
D. None of these
Given
Let y = vx
On integrating on both sides, we get
Conclusion: Therefore, is the solution of
Mark (√) against the correct answer in the following:
The general solution of the DE is.
A.
B.
C.
D. None of these
Given
Let y = vx
On integrating on both sides, we get
Conclusion: Therefore, is the solution of
Mark (√) against the correct answer in the following:
The general solution od the DE is
A.
B.
C.
D. None of these
Mark (√) against the correct answer in the following:
The general solution of the DE 2𝒳𝒴 𝒹𝒴 + (𝒳2 - 𝒴2) 𝒹𝒳 = 0 is
A. 𝒳2 + 𝒴2 = C𝒳
B. 𝒳2 + 𝒴2 = C𝒴
C. 𝒳2 + 𝒴2 = C
D. None of these
Given
Let y = vx
On integrating on both sides, we get
Conclusion: Therefore, is the solution of
Mark (√) against the correct answer in the following:
The general solution of the DE (𝒳 - 𝒴 ) 𝒹𝒴 + (𝒳 + 𝒴) 𝒹𝒳 is
A.
B.
C.
D. None of these
Given (x-y)dy + (x+y) dx = 0
Let y = vx
Question is wrong. I think subtraction should be there instead of addition in LHS(left hand side)
Mark (√) against the correct answer in the following:
The general solution of the DE is
A.
B.
C.
D. None of these
Given
Let y = vx
Conclusion: Therefore, is the solution of
Mark (√) against the correct answer in the following:
The general solution of the DE is
A. 𝒴 = sin 𝒳 – C cos 𝒳
B. 𝒴 = sin 𝒳 + C cos 𝒳
C. 𝒴 = cos 𝒳 – C sin 𝒳
D. None of these
Given
It is in the form
Integrating factor
General solution
y sec x = tan x + C
y = sin x + C cos x
Conclusion: Therefore, y = sin x + C cos x is the solution of
Mark (√) against the correct answer in the following:
The general solution of the DE is
A. (𝒴 + sin 𝒳)sin 𝒳 = C
B. (𝒴 + cos 𝒳 ) sin 𝒳 = C
C. (𝒴 – sin 𝒳 ) sin 𝒳 = C
D. None of these
Given
It is in the form
Integrating factor
General solution is
(y-sin x)sin x = C
Conclusion: Therefore, (y-sin x)sin x = C is the solution of
Mark (√) against the correct answer in the following:
The general solution of the DE is
A. 𝒳𝒴 = 𝒳4 + C
B. 4𝒳𝒴 = 𝒳4 + C
C. 3𝒳𝒴 = 𝒳3 + C
D. None of these
Given
It is in the form
Integrating factor
General solution is
Conclusion: Therefore, is the solution of