Evaluate the following :
Formula: –
(i)
(ii)
(iii)
we have
using Formula(i) and (iii)
therefore, using Formula (ii)
Evaluate the following :
Formula: -
(i)
(ii)
(iii)
Given: -
we have
using Formula (i)
using Formula (ii)
therefore,
Find when
and
Formula: -
(i)
(ii)
Given: -
using Formula(i)
now, using
= 2( – 1 – 0) + 3( – 1 + 3)
= – 2 + 6
= 4
therefore,
Find when
and
Formula: -
(i) If andthen,
(ii)
Given: -
now, using
= 1(1 + 1) + 2(2 + 0) + 3(2 – 0)
= 2 + 4 + 6 = 12
therefore,
Find the volume of the parallelepiped whose coterminous edges are represented by the vectors:
Formula : -
(i) if
(ii)
Given: -
we know that the volume of parallelepiped whose three adjacent edges are
we have
now, using
= 2(4 – 1) – 3(2 + 3) + 4( – 1 – 6)
= – 37
therefore, the volume of the parallelepiped is
Find the volume of the parallelepiped whose coterminous edges are represented by the vectors:
Formula : -
(i) ifandthen,
(ii)
Given: -
we know that the volume of parallelepiped whose three adjacent edges are
we have
now, using
= 2( – 4 – 1) – 3( – 2 + 3) + 4( – 1 – 6)
= – 35
therefore, the volume of the parallelepiped is
Find the volume of the parallelepiped whose coterminous edges are represented by the vectors:
Formula : -
Given: -
we know that the volume of parallelepiped whose three adjacent edges are
we have
now, using
= 11(26 – 0) + 0 + 0 = 286
therefore, the volume of the parallelepiped is
[a⃗ b⃗ c⃗] = |286| = 286 cubic unit.
Find the volume of the parallelepiped whose coterminous edges are represented by the vectors:
Formula: -
andthen,
Given: -
we know that the volume of parallelepiped whose three adjacent edges are
is equal to .
we have
now, using
= 1(1 – 2) – 1( – 1 – 1) + 1(2 + 1)
= 4
therefore, the volume of the parallelepiped is
= 4 cubic unit.
Show that each of the following triads of vectors is coplanar :
Formula : –
(iii)Three vectors a ⃗,b ⃗, and c ⃗are coplanar if and only if
Given: -
we know that three vector are coplanar if their scalar triple product is zero
we have
using
= 1(10 – 42) – 2(15 – 35) – 1(18 – 10)
= 0.
Hence, the Given vector are coplanar.
Show that each of the following triads of vectors is coplanar :
Formula : -
Given: -
we know that three vector are coplanar if their scalar triple product is zero
we have
now, using
= – 4(12 + 13) + 6( – 3 + 24) – 2(1 + 32)
= 0
hence, the Given vector are coplanar.
Show that each of the following triads of vectors is coplanar :
Formula : -
and then,
(iii) Three vectors are coplanar if and only if a⃗.(b⃗×c⃗) = 0
Given: -
we know that three vector a⃗,b⃗,c⃗ are coplanar if their scalar triple product is zero
we have
now, using
= 1(15 – 12) + 2( – 10 + 4) + 3(6 – 3)
= 3 – 12 + 9 = 0
Find the value of λ so that the following vectors are coplanar.
Formula : -
Given: -
we know that vector are coplanar if their scalar triple product is zero
we have
now, using
⇒ 0 = 1(λ – 1) + 1(2λ + λ) + 1( – 2 – λ)
⇒ 0 = λ – 1 + 3 λ – 2 – λ
⇒ 0 = 3 λ – 3
⇒ λ = 1
Find the value of λ so that the following vectors are coplanar.
Formula : -
Given: -
we know that vector are coplanar if their scalar triple product is zero
we have
now, using
⇒ 0 = 2(10 + 3λ) + 1(5 + 3λ) + 1(λ – 2λ)
⇒ 0 = 8 λ + 25
Find the value of λ so that the following vectors are coplanar.
Formula : -
Given: -
we know that vector are coplanar if their scalar triple product is zero
we have
now, using
⇒ 0 = 1(2 λ – 2) – 2(6 – 1) – 3(6 – λ)
⇒ 0 = 5 λ – 30
⇒ λ = 6
Find the value of λ so that the following vectors are coplanar.
Formula : -
andthen,
Given: -
we know that vector are coplanar if their scalar triple product is zero
we have
now, using
⇒ 0 = 1(0 + 5) – 3(0 – 5λ) + 0
⇒ 0 = 5 + 15λ
Show that the four points having position vectors are not coplanar.
Formula : -
andthen,
andthen
Given: -
The four points are coplaner if vector AB⃗,AC⃗,AD⃗ are coplanar.
now, using
= 10(100 + 72) + 12( – 60 – 24) – 4( – 72 + 40) = 840
≠0.
hence the point are not coplanar
Show that the points A( – 1, 4, – 3), B(3, 2, – 5), C( – 3, 8, – 5) and D( – 3, 2, 1) are coplanar.
Formula: -
Given: -
AB = position vector of B - position vector of A
AC = position vector of c - position vector of A
AD = position vector of c - position vector of A
The four pint are coplanar if the vector are coplanar.
thus,
now, using
= 4(16 - 4) + 2( - 8 - 4) - 2( - 4 + 8) = 0
hence proved.
Show that four points whose position vectors are are coplanar.
Formula : -
and then
(iii) Three vectorsare coplanar if and only if
(iv) If andthen,
let
The four points are coplanar if the vector are coplanar.
now, using
= 10(100 + 12) + 12( – 60 – 24) – 4( – 12 + 40) = 0.
hence the point are coplanar
Find the value of for which the four points with position vectors and are coplanar.
Formula : -
andthen
(iii) Three vectors are coplanar if and only if
(iv) ifandthen,
Given: -
The four points are coplaner if vector AB⃗,AC⃗,AD⃗ are coplanar.
now, using
⇒ 4(50 – 25) – 6(15 + 20) + (λ + 1)(15 + 40) = 0.
⇒ λ = 1
hence the point are coplanar
Prove that : -
Formula: -
taking L.H.S
using Formula (i)
using Formula(ii)
L.H.S = R.H.S
and are the position vectors of points A, B and C respectively, prove that : is a vector perpendicular to the plane of triangle ABC.
if represents the sides AB,
if represent the sides BC,
if respresent the sidesAC of triangle ABC
is perpendicular to plane of triangle ABC. …… (i)
is perpendicular to plane of triangle ABC. …… (ii)
is perpendicular to plane of triangle ABC. …… (iii)
adding all the (i) + (ii) + (iii)
hence is a vector perpendicular to the plane of the triangle ABC
Let and Then,
If and find which makes and coplanar.
Formula: -
Given: -
are coplanar if
now, using
⇒ 0 – 1(c3) + 1(2) = 0
⇒ c3 = 2
Let and Then,
If and show that no value of can make and coplanar.
Formula: -
andthen,
(iii)Three vectors are coplanar if and only if
we know that are coplanar if
now, using
⇒ 0 – 1(c3) + 1(2) = 0
⇒ c3 = 2
Find for which the points A(3, 2, 1), B(4, λ, 5), C(4, 2, – 2) and D(6, 5, – 1) are coplanar.
Formula: -
and then,
let position vector of
position vector of
position vector of
position vector of
The four points are coplanar if the vector are coplanar
now, using
⇒ 1(9) – (λ – 2)( – 2 + 9) + 4(3 – 0) = 0
⇒ 7λ = 35
⇒ λ = 5
If four points A, B, C and D with position vectors and respectively are coplanar, then find the value of x.
Formula: -
(iii) Three vectors a⃗ ,b⃗ , and c⃗ are coplanar if and only if a⃗.(b⃗×c⃗) = 0
let position vector of
position vector of
position vector of
position vector of
The four points are coplanar if the vector are coplanar
⇒ 1(9) – (x – 2)( – 2 + 9) + 4(3) = 0
⇒ 9 – 7x + 14 + 12 = 0
⇒ 35 = 7x
⇒ x = 5
The meaning of the notation is the scalar triple product of the three vectors; which is computed as
So we have ()
Write the value of
Here we have
=
Write the value of
The value of the above product is the value of the matrix
Find the values of ‘a’ for which the vectors and are coplanar.
Three vectors are coplanar iff (if and only if)
Hence we have value of the matrix
We have 2a2-3a+1=0
2a2-2a-a+1=0
Solving this quadratic equation we get
Find the volume of the parallelepiped with its edges represented by the vectors
Volume of the parallelepiped with its edges represented by the vectors is
==
If are non-collinear vectors, then find the value of
for any vector
We have
Replacing =
If the vectors (sec2 A) are coplanar, then find the value of cosec2A A + cosec2B + cosec2C.
For three vectors to be coplanar we have
Which gives ………(1)
………(2)
Substituting equation 2 in 1 we have
Let
So we have
=(x-2)(y-2)(z-2)-(x-2)(y-1)(z-1)-(x-1)(y-2)(z-1)-(x-1)(y-1)(z-2)+2(x-1)(y-1)(z-1)=0
Solving we have x+y+z=4
Hence cosec2A + cosec2B + cosec2C = 4
For any two vectors of of magnitudes 3 and 4 respectively, write the value of
the dot and cross can be interchanged in scalar triple product.
Let the angle between vector be
=144 sin2 θ+144 cos2 θ
=144(1)
=144
If then find the value of λ + μ.
λ = 3
μ = 1
So, λ + μ = 3 + 1
= 4
If are non-coplanar vectors, then find the value of
the dot and cross can be interchanged in scalar triple product.
Also (cyclic permutation of three vectors does not change the value of the scalar triple product)
=
Using these results
Find , if and
Mark the correct alternative in each of the following:
If lies in the plane of vectors and , then which of the following is correct?
A.
B.
C.
D.
Here, lies in the plane of vectors and , which means , and are coplanar.
We know that is perpendicular to and .
Also dot product of two perpendicular vector is zero.
Since, , , are coplanar, is perpendicular to .
So,
Mark the correct alternative in each of the following:
The value of , where ,, is
A. 0
B. 1
C. 6
D. none of these
= 0
Mark the correct alternative in each of the following:
If , , are three non-coplanar mutually perpendicular unit vectors, then is
A. ±1
B. 0
C. –2
D. 2
Here, ⊥ ⊥ and .
⇒ angle between and is or .
= ±1
Mark the correct alternative in each of the following:
If for some non-zero vector , then the value of , is
A. 2
B. 3
C. 0
D. none of these
Here,
, and are coplanar.
Mark the correct alternative in each of the following:
For any three vector the expression equals
A.
B.
C.
D. none of these
=
= 0
Mark the correct alternative in each of the following:
If , , are non-coplanar vectors, then is
A. 0
B. 2
C. 1
D. none of these
=0
Mark the correct alternative in each of the following:
Let and be three non-zero vectors such that c⃗ is a unit vector perpendicular to both a⃗ and b⃗ . If the angle between a⃗ and b⃗ is, then is equal to
A. 0
B. 1
C.
D.
(∵ c⃗ is perpendicular to a⃗ and b⃗ ⇒ angle is 0)
(∵ c⃗ is unit vector )
Mark the correct alternative in each of the following:
If and then the volume of the parallelepiped with conterminous edges , , is
A. 2
B. 1
C. –1
D. 0
Let
Now,the volume of the parallelepiped with conterminous edges , , is given by
=5× (-21+18)+7× (24-21)+10× (-48+49) ×
=5× (-3)+7× 3+10× 1
=-15+21+10
=16
Mark the correct alternative in each of the following:
If then
A. 6
B. –6
C. 10
D. 8
Now, comparing the coefficient of lhs and rhs we get, λ=2 and μ=4
∴ λ + μ = 2+4
=6
Mark the correct alternative in each of the following:
A.
B.
C.
D. 2
Mark the correct alternative in each of the following:
If the vectors and are coplanar, then m =
A. 0
B. 38
C. –10
D. 10
Here, vector a, b, and c are coplanar. So, .
∴
∴ 4(8-30)-11(28-6)+m(35-2)= 0
∴ 4(-22)-11(22)+33m = 0
∴ -88 -242 +33m = 0
∴ 33m = 330
∴ m = 10
Mark the correct alternative in each of the following:
For non-zero vectors a⃗, b⃗ and c⃗ the relation holds good, if
A.
B.
C.
D.
Let
--------(1) (∵ α is angle between a⃗ and b⃗ )
Then
(∵θ is angle between e⃗ and c⃗ ⇒ θ is angle between a⃗ Xb⃗ and c⃗ )
(∵ using (1))
Hence, if and only if
if and only if and
if and only if and
⇒ a⃗ and b⃗ are perpendicular.
Also e⃗ is perpendicular to both a⃗ and b⃗ .
θ=0⇒ c⃗ is perpendicular to both a⃗ and b⃗
∴ a⃗, b⃗, c⃗ are mutually perpendicular.
∴ a⃗∙ b⃗=b⃗∙ c⃗=c⃗∙ a⃗=0
Mark the correct alternative in each of the following:
A. 0
B.
C.
D.
Mark the correct alternative in each of the following:
If a⃗ ,b⃗,c⃗ are three non-coplanar vectors, then equal.
A. 0
B.
C. 2
D.
+ []
+ [c⃗ b⃗ a⃗] + + 0
Mark the correct alternative in each of the following:
is equal to
A.
B. 2
C. 3
D. 0
+