Every integer less than 0 has the sign
A. +
B. –
C. ×
D. ÷
On the number line every number to the left of zero is represented with a ‘-‘ sign.
The integer ‘5 units to the right of 0 on the number line’ is
A. +5
B. –5
C. +4
D. – 4
On the number line every number to the right of zero is represented with a ‘+‘ sign. Thus at a distance of 5 units there is +5.
The predecessor of the integer –1 is
A. 0
B. 2
C. –2
D. 1
Predecessor means before. To find the predecessor subtract one from the number. Thus the number before -1 on the number line is -2.
Number of integers lying between –1 and 1 is
A. 1
B. 2
C. 3
D. 0
Zero is the only integer between -1 and 1.
Number of whole numbers lying between –5 and 5 is
A. 10
B. 3
C. 4
D. 5
Since whole numbers begin only from 0, thus 0,1,2,3,4 are the numbers between -5 and 5. Thus there are only 5 numbers.
The greatest integer lying between –10 and –15 is
A. –10
B. –11
C. –15
D. –14
In the case of negative numbers of the higher the number the lower the value. Thus the least value is the greatest and it is -11.
The least integer lying between –10 and –15 is
A. –10
B. –11
C. –15
D. –14
In case of negative numbers, higher the number lower the value. Thus -14 is least integer.
On the number line, the integer 5 is located
A. to the left of 0
B. to the right of 0
C. to the left of 1
D. to the left of –2
5 is a positive number and thus is to the right of 0 on the number.
In which of the following pairs of integers, the first integer is not on the left of the other integer on the number line?
A. (–1, 10)
B. (–3, –5)
C. (–5, –3)
D. (–6, 0)
It is the only case where the first integer is greater than the second integer.
The integer with negative sign (–) is always less than
A. 0
B. –3
C. –1
D. –2
All the negative numbers lie to the left of zero on the number line. Thus any number with – sign is always less than 0.
An integer with positive sign (+) is always greater than
A. 0
B. 1
C. 2
D. 3
All positive numbers lie to the right of zero, thus they are greater than 0.
The successor of the predecessor of –50 is
A. –48
B. –49
C. –50
D. –51
To find the successor we add 1 to find the predecessor we subtract 1, thus we get -50 + 1 -1 = -50. Since they cancel each other out, the answer -50.
The additive inverse of a negative integer
A. is always negative
B. is always positive
C. is the same integer
D. Zero
Additive inverse of a number means, if we add the additive inverse to the number we get 0. Thus for any negative integer, we have to add a positive integer to make it zero.
Amulya and Amar visited two places A and B respectively in Kashmir and recorded the minimum temperatures on a particular day as –4°C at A and –1°C at B. Which of the following statement is true?
A. A is cooler than B
B. B is cooler than A
C. There is a difference of 2°C in the temperature
D. The temperature at A is 4°C higher than that at B.
A is cooler than B, since -4 is lesser than -1 as it lies to the left of -1. Option C is wrong since the difference between them is 3 and not 2. Option D is incorrect since A is 3 degrees lesser than B and not 4 degrees higher.
When a negative integer is subtracted from another negative integer, the sign of the result
A. is always negative
B. is always positive
C. is never negative
D. depends on the numerical value of the integers
The answer depends on the numerical value. Take for example -5. -5 – (-8) = -5 + 8 = +3. -5 – (-3) = -5 + 3 = -2. So we can get either a positive or negative value depending on the number.
The statement “When an integer is added to itself, the sum is greater than the integer” is
A. always true
B. never true
C. true only when the integer is positive
D. true for non-negative integers
This is true only for positive integers. Option D is incorrect since 0+0=0, and zero is not greater than itself.
Which of the following shows the maximum rise in temperature?
A. 0°C to 10°C
B. –4°C to 8°C
C. –15°C to –8°C
D. –7°C to 0°C
Option B has a difference of 8-(-4) = 8 + 4 = 12, while option A has a difference of 10, option C and D have difference of 7.
The smallest natural number is zero.
True
The natural numbers are non-negative numbers.
Example:
Zero is not an integer as it is neither positive nor negative.
False
Zero is an integer. Though it is neither called negative or positive.
The sum of all the integers between –5 and –1 is –6.
The sum of the integers is:
-5 + (-1) = - 6
Same sign integers add and different sign integers subtract.
The successor of the integer 1 is 0.
False, Successor of a number is obtained by adding 1 to it. So successor of 1 would be 2.
Every positive integer is larger than every negative integer.
True, Positive numbers are always greater than negative numbers.
The sum of any two negative integers is always greater than both the integers.
False, e.g. , the answer is less than both the integers.
The sum of any two negative integers is always smaller than both the integers.
True, As you can see in the previous example.
The sum of any two positive integers is greater than both the integers.
True, e.g. 21+12=31, 31 is greater than both the numbers.
All whole numbers are integers.
True, Whole Numbers are 0,1,2,3….. and Integers are -2,-1,0,1,2…. All whole Numbers are Integers.
All integers are whole numbers.
False, As you can see in the previous example, Integers are negative numbers too. But whole numbers are 0,1,2,3….
Since 5 > 3, therefore –5 > –3
False, an integer on left side of given number is always smaller than the given number
Zero is less than every positive integer.
True, Number on the left side of given number is always smaller than the given number. Zero is always on the left side of every positive number so it would be less than every positive number.
Zero is larger than every negative integer.
True,
The number on the right side of the given number is always greater than the given number. Zero is on the right side of every negative number so it would be greater than the negative number.
Zero is neither positive nor negative.
True,
Zero is neither positive nor negative.
On the number line, an integer on the right of a given integer is always larger than the integer.
True,
The number line is shown here:
You can see here, 6 is on the right side 5 so 6>5.
–2 is to the left of –5 on the number line.
False,
You can see in this figure.
The smallest integer is 0.
False,
Integers are -3,-2,-1,0,1,2,3…. So 0 is not a smallest integer.
6 and –6 are at the same distance from 0 on the number line.
True,
Clearly, We can see that -6 and 6 are at the same distance of 6 units from 0.
The difference between an integer and its additive inverse is always even.
True, the additive inverse of a number a is the number that, when added to a, yields zero.
e.g. additive inverse of 12 is -12. Difference of these two is 12-(-12)=24, which is even.
The sum of an integer and its additive inverse is always zero.
True, the additive inverse of a number a is the number that, when added to a, yields zero.
So sum of integer and its additive integer is always zero.
The sum of two negative integers is a positive integer.
False, e.g. -12+(-23)=-35, sum is negative.
The sum of three different integers can never be zero.
False, e.g. sum of 9, 2 and -11 is zero.
On the number line, –15 is to the _______ of zero.
left
Negative integers lie on the left of zero.
On the number line, 10 is to the _______ of zero.
right
Positive integers lie on the left of zero.
The additive inverse of 14 is _______.
-14
Additive inverses are negatives of each other.
Additive inverse of +14 is .
The additive inverse of –1 is _______.
1
Additive inverses are negatives of each other. Additive inverse of -1 is .
The additive inverse of 0 is _______.
0
Zero is the only number with additive inverse equal to itself.
The number of integers lying between –5 and 5 is _______.
9
The integers -4, -3, -2, -1, 0, 1, 2, 3 and 4 lie between –5 and 5. So, nine integers lie between –5 and 5.
(–11) + (–2) + (–1) = ________.
-14
To add negative integers, we add the corresponding positive integers and retain the negative sign with the sum.
_______ + (–11) + 111 = 130
30
To add a positive integer and a negative integer, we ignore the signs and subtract integer with smaller numerical value from the integer with larger numerical value and take the sign of the larger one.
Since 111 is the larger of the two numbers, positive sign is retained.
The missing value is 30.
(–80) + 0 + (–90) = _______
-170
To add negative integers, we add the corresponding positive integers and retain the negative sign with the sum.
_______ –3456 = –8910
-5454
To add a positive integer and a negative integer, we ignore the signs and subtract integer with smaller numerical value from the integer with larger numerical value and take the sign of the larger one.
Since 8910 is the larger of the two numbers, negative sign is retained.
The missing value is -5454.
(–11) + (–15) _______ 11 + 15
<
LHS:
To add negative integers, we add the corresponding positive integers and retain the negative sign with the sum.
RHS:
(–71) + (+9) _______ (–81) + (–9)
>
LHS:
To add a positive integer and a negative integer, we ignore the signs and subtract integer with smaller numerical value from the integer with larger numerical value and take the sign of the larger one.
Since 71 is the larger of the two numbers, negative sign is retained.
RHS:
To add negative integers, we add the corresponding positive integers and retain the negative sign with the sum.
0 _______ 1
<
Since 0 lies to the left of 1, 0 < 1.
0 is smaller than all positive integers.
–60 _______ 50
<
Positive integers are greater than negative integers.
–10 _______ –11
>
For two negative integers, the one closer to zero is always greater.
–101 _______ –102
>
For two negative integers, the one closer to zero is always greater.
(–2) + (–5) + (–6) _______ (–3) + (–4) + (–6)
=
LHS:
RHS:
0 _______ –2
>
-2 lies to the left of 0. So, 0 > -2.
1 + 2 + 3 _______ (–1) + (–2) + (–3)
>
LHS:
RHS:
To add a positive integer and a negative integer, we ignore the signs and subtract integer with smaller numerical value from the integer with larger numerical value and take the sign of the larger one.
Since 3 is the larger of the numbers, negative sign is retained.
Match the items of Column I with that of Column II:
(i) B
Additive inverses are negatives of each other. So, additive inverse of +2 is -2.
(ii) E
In case of negative integers, the one closer to zero is always greater. -1 is closest to zero.
(iii) B
Negative even integers are -2, -4, -6,.. . Out of them, -2 is greatest.
(iv) A
0 is the smallest integer greater than every negative integer.
(v) B
Predecessor of -1 is -2
Successor of -1 is 0.
Sum of predecessor and successor of -1 = -2 + 0 = -2.
Compute each of the following:
(a) 30 + (–25) + (–10)
(b) (–20) + (–5)
(c) 70 + (–20) + (–30)
(d) –50 + (–60) + 50
(e) 1 + (–2) + (– 3) + (– 4)
(f) 0 + (– 5) + (– 2)
(g) 0 – (–6) – (+6)
(h) 0 – 2 – (–2)
(a) -5
(b) -25
(c) 20
(d) -60
-50 and 50 are additive inverse of each other, i.e. their sum is zero.
(e) -8
(f) -7
(g) 0
(h) 0
If we denote the height of a place above sea level by a positive integer and depth below the sea level by a negative integer, write the following using integers with the appropriate signs:
a) 200 m above sea level
b) 100 m below sea level
c) 10 m above sea level
d) sea level
A. + 200 m
B. -100 m
C. + 10 m
D. 0 m
Write the opposite of each of the following:
a) Decrease in size
b) Failure
c) Profit of Rs.10
d) 1000 A.D.
e) Rise in water level
f) 60 km south
g) 10 m above the danger mark of river Ganga
h) 20 m below the danger mark of the river Brahmaputra
i) Winning by a margin of 2000 votes
j) Depositing Rs.100 in the Bank account
k) 20°C rise in temperature.
a) Increase in size
b) Success
c) Loss of Rs. 10
d) 1000 B.C.
e) Drop in water level
f) 60 km north
g) 10 m below the danger mark of river Ganga
h) 20 m above the danger mark of the river Brahmaputra
i) Losing by a margin of 2000 votes
j) Withdrawing Rs. 100 from the Bank Account
k) 20°C fall in temperature
Temperature of a place at 12:00 noon was + 5°C. Temperature increased by 3°C in first hour and decreased by 1°C in the second hour. What was the temperature at 2:00 pm?
Temperature at 12:00 noon = + 5°C
∴ Temperature at 1:00 pm = ( + 5 + 3) = + 8°C
∴ Temperature at 2:00 pm = ( + 8 -1) = + 7°C
Write the digits 0, 1, 2, 3, ..., 9 in this order and insert ‘ + ’ or ‘–’ between them to get the result 3.
The given digits are 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.
Now to get result 3,
⇒ 0 + 1 + 2 + 3 – 4 + 5 + 6 + 7 – 8 – 9
⇒ 24 – 21
⇒ 3
Write the integer which is its own additive inverse.
0 is the integer which is its own additive inverse.
∵ 0 + (-0) = 0
Write six distinct integers whose sum is 7.
Six distinct integers are -1, 0, 1, -3, 3, 7.
The sum of the numbers,
⇒ -1 + 0 + 1 – 3 + 3 + 7
⇒ 0 + 7
⇒ 7
Write the integer which is 4 more than its additive inverse.
Let, the integer is A and its additive inverse is x.
∴ A + x = 0
⇒ x = - A
According to problem,
⇒ A = - A + 4
⇒ 2A = + 4
⇒ A = + 2
∴ The integer is = + 2
Write the integer which is 2 less than its additive inverse.
Let, the integer is A and its additive inverse is x.
∴ A + x = 0
⇒ x = - A
According to problem,
⇒ A = - A – 2
⇒ 2A = - 2
⇒ A = -1
∴ The integer is = -1
Write two integers whose sum is less than both the integers.
Sum of any two negative integers is less than both the integers.
Let, two integers are – 4 and – 7.
∴ -4 + -7 = -11
We know, -11<-4,-7
Write two distinct integers whose sum is equal to one of the integers.
When we add 0 to any other integer the sum is equal to that integer.
Let, 0 and 5 are two distinct integers.
We know, 0 + 5 = 5
Using number line, how do you compare
A. two negative integers?
B. two positive integers?
C. one positive and one negative integer?
A. If we compare two negative integers on the number line, then the number which is on the left to the other number, is the smaller number.
B. If we compare two positive integers on the number line, then the number which is on the left to the other number, is the smaller number.
C. On the number line positive numbers lie on the right of zero and negative numbers lie on the left of zero. So, negative numbers is always on the left of the positive numbers, hence negative numbers are always smaller than positive numbers.
As we can see -5 < -2
+ 2 < + 4
-3 < + 3
Observe the following:
1 + 2 – 3 + 4 + 5 – 6 – 7 + 8 – 9 = –5
Change one ‘–’ sign as ‘ + ’ sign to get the sum 9.
We can observe that,
⇒ 1 + 2 – 3 + 4 + 5 – 6 – 7 + 8 – 9
⇒ (1 + 2 – 3) + (4 + 5 – 9) – 6 – 7 + 8
⇒ 0 + 0 + 2 – 7
⇒ 2 – 7
If we change the sign of 7 from ‘–’ to ‘ + ’ it would become,
⇒ 2 + 7
⇒ 9
Arrange the following integers in the ascending order:
–2, 1, 0, –3, + 4, –5
The ascending order of the following numbers :-
-5 < -3 < -2 < 0 < 1 < + 4
Arrange the following integers in the descending order:
–3, 0, –1, –4, –3, –6
The descending order of the following numbers :-
0 > -1 > -3 > -4 > -6
Write two integers whose sum is 6 and difference is also 6.
The required integers are 0 and 6
We know, 0 + 6 = 6
Also, 6 – 0 = 6
Write five integers which are less than –100 but greater than –150.
Five integers which are less than -100 but greater than -150 are →
-105, -117, -123, -137 and -145
Write four pairs of integers which are at the same distance from 2 on the number line.
(1,3) → both are at a distance of 1 unit from 2
(0,4) → both are at a distance of 2 units from 2
(-1,5) → both are at a distance of 3 units from 2
(-2,6) → both are at a distance of 4 units from 2
The sum of two integers is 30. If one of the integers is –42, then find the other.
Let, the other integer is = x
According to problem,
⇒ x + (-42) = 30
⇒ x = 30 + 42
⇒ x = + 72
Sum of two integers is –80. If one of the integers is –90, then find the other.
Let, the other integer is = x
According to problem,
⇒ x + (-90) = -80
⇒ x = -80 + 90
⇒ x = + 10
If we are at 8 on the number line, in which direction should we move to reach the integer
A. –5 B. 11 C. 0?
A. From 8 we have to move in left on the number line to reach at -5
B. From 8 we have to move in right on the number line to reach at 11.
C. From 8 we have to move in left on the number line to reach at 0
Using the number line, write the integer which is
A. 4 more than –5
B. 3 less than 2
C. 2 less than –2
A. To get the integer 4 more than -5, we have to move 4 steps towards right from -5 on the number line and reach at – 1.
∴ The integer 4 more than -5 = -1
B. To get the integer 3 less than 2, we have to move 3 steps towards left from 2 on the number line and reach at – 1.
∴ The integer 3 less than 2 = -1
C. To get the integer 2 less than -2, we have to move 2 steps towards left from -2 on the number line and reach at – 4.
∴ The integer 2 less than -2 = -4
Find the value of
49 – (–40) – (–3) + 69
⇒ 49 – (–40) – (–3) + 69
⇒ 49 + 40 + 3 + 69
⇒ 161
Subtract –5308 from the sum [(–2100) + (–2001)]
If we Subtract –5308 from the sum [(–2100) + (–2001)],
⇒ [(-2100) + (-2001)] – (-5308)
⇒ [-2100 – 2001] + 5308
If both numbers have a negative sign they are added and in the answer negative sign is put before the value.⇒ - 4101 + 5308
If one number has a positive sign and other has negative, then numbers are subtracted and the sign of the greater number is put before it.⇒ 1207