Respiration in insects is called direct because
A. The cell exchange O2/ CO2 directly with the air in the tubes
B. The tissues exchange O2/ CO2 directly with coelomic fluid
C. The tissues exchange O2/ CO2 directly with the air outside through body surface
D. Tracheal tubes exchange O2/ CO2 directly with the haemocoel which then exchange with tissues
Direct respiration means exchange of gases without using any special respiratory organ and blood. In case of insects, the tracheal tubes exchange oxygen and carbon dioxide with the haemocoel which then exchange then with tissues.
Regarding the functions of our respiratory system, mark the wrong entry.
A. Humidifies the air
B. Warms up the air
C. Exchange of gases
D. Cleans up the air
•The function of the respiratory system is to move two gases: oxygen and carbon dioxide. Gas exchange takes place in the millions of alveoli in the lungs and the capillaries that envelop them.
•The respiratory system has built-in methods to prevent harmful substances in the air from entering the lungs. Hairs in your nose help filter out large particles. Microscopic hairs, called cilia, are found along your air passages and move in a sweeping motion to keep the air passages clean.
•As air passes through the nasal cavities it is warmed and humidified, so that air that reaches the lungs is warmed and moist.
A person suffers punctures in his chest cavity in an accident without any damage to the lungs. Its effect could be
A. Reduced breathing rate
B. Rapid increase in breathing rate
C. No change in respiration
D. Cessation of breathing
Breathing takes place due to pressure gradient between the chest cavity and the atmosphere. Puncture in a person’s chest cavity causes the loss of pressure gradient hence leading to stoppage of breathing.
It is known that exposure to carbon monoxide is harmful to animals because
A. It reduces CO2 transport
B. It reduces O2 transport
C. It increases CO2 transport
D. It increases O2 transport
Carbon dioxide is a harmful poisonous gas. It has more affinity towards haemoglobin than oxygen. When a person inhales Carbon Monoxide, the Carbon Monoxide binds to the Haemoglobin and forms a very stable combination called Carboxy-haemoglobin. It leads to suffocation as carbon monoxide does not disassociate from haemoglobin which makes it unable for oxygen to bind to the haemoglobin and hence reduces oxygen transport.
Mark the true statement among the following with reference to normal breathing
A. Inspiration is a passive process where as expiration is active
B. Inspiration is a active process where as expiration is passive
C. Inspiration and expiration are active processes
D. Inspiration and expiration are passive processes
An active process is one in which energy and work is required. Inhalation is an active process because it requires energy and work in contraction of the diaphragm downwards so as to make room for air in the lungs.
Passive process is one in which there is no requirement of energy and work. Expiration is a passive process because it does not require energy and work in the relaxation of the diaphragm.
A person breathes in some volume of air by forced inspiration after having a forced expiration. This quantity of air taken in is
A. Total lung capacity
B. Tidal volume
C. Vital capacity
D. Inspiratory capacity
Mark the incorrect statement in context to O2 binding to Hb
A. Higher pH
B. Lower temperature
C. Lower pCO2
D. Higher PO2
O2 binding to Hb occurs when there is:
1. Lower temperature
2. Lower pCO2
3. Higher PO2
Mark the correct pair of muscles involved in the normal breathing in humans.
A. External and internal intercostals muscles
B. Diaphragm and abdominal muscles
C. Diaphragm and external intercostal muscles
D. Diaphragm and internal intercostals muscles
The diaphragm and a specialised set of muscles, called external intercostals muscles present between the ribs are involved in the normal breathing in humans. They are involved in generating pressure gradient of air between the lungs and the atmosphere, so as to facilitate the intake of air.
Incidence of Emphysema – a respiratory disorder is high in cigarette smokers. In such cases
A. The bronchioles are found damaged
B. The alveolar walls are found damaged
C. The plasma membrane is found damaged
D. The respiratory muscles are found damaged
Emphysema is a disorder in which the alveoli or air sacs get damaged which leads to decreased availability of oxygen.This disorder is mainly caused by cigarette smoking.
Respiratory process is regulated by certain specialized centres in the brain. One of the following centres can reduce the inspiratory duration upon stimulation
A. Medullary inspiratory centre
B. Pneumotaxic centre
C. Apneustic centre
D. Chemosensitive centre
CO2 dissociates from carbaminohaemoglobin when
A. pCO2 is high & pO2 is low
B. pO2 is high and pCO2 is low
C. pCO2 and pO2 are equal
D. None of the above
CO2 dissociates from carbaminohaemoglobin when pO2 is high and pCO2 is low .
In breathing movements, air volume can be estimated by
A. Stethoscope
B. Hygrometer
C. Sphygmomanometer
D. Spirometer
From the following relationships between respiratory volume and capacities and mark the correct answer
i. Inspiratory capacity (IC) = Tidal Volume + Residual Volume
ii. Vital Capacity (VC) = Tidal Volume (TV) + Inspiratory Reserve Volume (IRV) + Expiratory Reserve Volume (ERV).
iii. Residual Volume (RV) = Vital Capacity (VC) – Inspiratory Reserve Volume (IRV)
iv. Tidal Volume (TV) = Inspiratory Capacity (IC) – Inspiratory Reserve Volume (IRV) Options:
A. (i) Incorrect, (ii) Incorrect, (iii) Incorrect, (iv) Correct
B. (i) Incorrect, (ii) Correct, (iii) Incorrect, (iv) Correct
C. (i) Correct, (ii) Correct, (iii) Incorrect, (iv) Correct
D. (i) Correct, (ii) Incorrect, (iii) Correct, (iv) Incorrect
(i) Incorrect, (ii) Correct, (iii) Incorrect, (iv) Correct
The oxygen - haemoglobin dissociation curve will show a right shift in case of
A. High pCO2
B. High pO2
C. Low pCO2
D. Less H+ concentration
The oxygen - haemoglobin dissociation curve will show a right shift in case of
1. Increased Temperature
2. Increased pCO2
3. Decreased pH
Match the following and mark the correct options
Options:
A. A-ii, B-i, C-iv, D-iii
B. A-i, B-iv, C-ii, D-iii
C. A-i, B-iii, C-ii, D-iv
D. A-i, B-ii, C-iv, D-iii
Define the following terms?
a. Tidal volume
b. Residual volume
c. Asthma
a. Tidal Volume: Volume of air inhaled and exhaled during a normal breathing cycle without any forced breathing is tidal volume.The normal range of tidal volume in a young adult is 500 ml per inspiration.
b. Residual Volume:Volume of air left in the lungs even after forced exhalation is called as residual volume. The normal range of residual volume in a young adult is 1100-1200 ml.
c. Asthma:It is an inflammatory disease of the airways of the lungs. Due to which the airway gets narrowed and excess mucus secretion takes place resulting in breathing difficulty.
Symptoms of Asthma:
1. Wheezing
2. Breathing Difficulty
3. Coughing
A fluid filled double membranous layer surrounds the lungs. Name it and mention its important function.
A fluid filled double membranous layer surrounds the lungs is called Pleura.
Functions of pleura:
1. The space between the pleura also known as pleural cavity consists of a fluid called pleural fluid.This fluid lubricates and helps the two pleural tissue to slide easily against each other during respiratory movements.
Name the primary site of exchange of gases in our body?
1.The primary site of exchange of gases in our body is Alveoli.Alveoli are small balloon like structures having thin walls and have numerous thin capillaries in contact with them.
2.Inhaled oxygen from the air reaches the alveoli and diffuses into the capillaries due to difference in the pressure gradient.
3.Carbon dioxide from the blood diffuses into the alveoli similarly and is exhaled.
Cigarette smoking causes emphysema. Give reason.
Emphysema is a disorder in which the alveoli wall gets damaged.Excessive cigarette smoking leads to Emphysema due to the presence of various harmful chemicals like nicotine, tar, sulphur etc. Which causes damage to the alveoli wall and also decreases elasticity of the bronchioles and alveoli.
What is the amount of O2 supplied to tissues through every 100 ml. of oxygenated blood under normal physiological conditions?
The amount of O2 supplied to tissues through every 100 ml. of oxygenated blood under normal physiological conditions is around 5ml.
A major percentage (97%) of O2 is transported by RBCs in the blood. How does the remaining percentage (3%) of O2 transported?
A major percentage (97%) of O2 is transported by RBCs in the blood and the remaining percentage (3%) of O2 transported through plasma.
Arrange the following terms based on their volumes in an ascending order
a. Tidal Volume (TV)
b. Residual Volume (RV)
c. Inspiratory Reserve Volume (IRV)
d. Expiratory Capacity (EC)
Hence, the arrangement of these terms according to their volume in ascending order would be :
Tidal Volume (TV) <Residual Volume (RV) <Expiratory Capacity (EC) <Inspiratory Reserve Volume (IRV) .
Complete the missing terms
a. Inspiratory Capacity (IC) = _____ +IRV
b. ___________________ = TV + ERV
c. Functional Residual Capacity (FRC) = ERV + ____
a. Inspiratory Capacity (IC) = _Tidal Volume (TV)____ +IRV
b. _______Expiratory Capacity____________ = TV + ERV
c. Functional Residual Capacity (FRC) = ERV + ____ Residual Volume
Name the organs of respiration in the following organisms:
a. Flatworm - _________________________________________
b. Birds - _____________________________________________
c. Frog- ______________________________________________
d. Cockroach - ________________________________________
Name the important parts involved in creating a pressure gradient between lungs and the atmosphere during normal respiration.
The important parts involved in creating a pressure gradient between lungs and the atmosphere during normal respiration are :
1. Diaphragm
2. Internal Intercostal Muscles of the ribs
3. External Intercostal Muscles of the ribs
State the different modes of CO2 transport in blood.
Around 75% of the CO2 is transported via blood and the remaining 25 % of it is transported via plasma.The three main ways by which CO2 is transported in blood are:
1. In Red blood cells carbon dioxide combines with water and forms carbonic acid. It is an unstable form and gets disassociated into hydrogen and bicarbonate ion.
2. Carbon dioxide is also transported through plasma in the form of bicarbonate ions.
Compared to O2, diffusion rate of CO2 through the diffusion membrane per unit difference in partial pressure is much higher. Explain.
Diffusion rate of any gas depends upon the solubility rate of the gas. Diffusion rate is directly proportional to the solubility rate.As the solubility of Carbon dioxide is much higher than oxygen it’s diffusion rate through the diffusion membrane per unit difference in partial pressure is much higher.
For completion of respiration process, write the given steps in sequential manner
a. Diffusion of gases (O2 and CO2) across alveolar membrane.
b. Transport of gases by blood.
c. Utilisation of O2 by the cells for catabolic reactions and resultant release of CO2.
d. Pulmonary ventilation by which atmospheric air is drawn in and CO2 rich alveolar air is released out.
e. Diffusion of O2 and CO2 between blood and tissues.
The correct sequence would be:
1. Pulmonary ventilation by which atmospheric air is drawn in and CO2 rich alveolar air is released out.
2.Diffusion of gases (O2 and CO2) across alveolar membrane.
3.Transport of gases by blood.
4.Diffusion of O2 and CO2 between blood and tissues.
5.Utilisation of O2 by the cells for catabolic reactions and resultant release of CO2.
So, the correct sequence would be d,a ,b, e and c.
Differentiate between
a. Inspiratory and expiratory reserve volume
b. Vital capacity and total lung capacity
c. Emphysema and occupational respiratory disorder
a.
b.
C.
Explain the transport of O2 and CO2 between alveoli and tissue with diagram.
Transportation of oxygen:
1. When oxygen is inhaled it reaches the alveoli (tiny balloon like structures which are in close proximity of various thin capillaries).
2. Now, the partial pressure of oxygen is more in the alveoli than the capillaries .
3. This causes the diffusion of oxygen into the capillaries
4. After which oxygen combines with Haemoglobin to form oxyhaemoglobin
5. This oxygenated blood reaches the organs which have low partial pressure than the capillaries.
6. In these organs the bond between oxygen and haemoglobin becomes unstable and breaks releasing oxygen into the organs.
Transportation of Carbon Dioxide:
Carbon dioxide is transported by three different methods which are :
3. Blood carries released carbon dioxide from various organs to the alveoli via capillaries which have lower intra pulmonary pressure than the organs.
4. Now, carbon dioxide is then diffused into the alveoli from the capillaries due to lower intra pulmonary pressure in the alveoli than the capillaries
5. In Red blood cells carbon dioxide combines with water and forms carbonic acid. It is an unstable form and gets disassociated into hydrogen and bicarbonate ion.
6. Carbon dioxide is also transported through plasma in the form of bicarbonate ions.
Explain the mechanism of breathing with neat labelled sketches.
Breathing is the process by which oxygen is inhaled into the body also known as inspiration and carbon dioxide is released outside the body also called as expiration.
Mechanism of breathing involves two processes which are:
A. Inspiration
B. Expiration
Inspiration: It is the process of taking in external air or oxygen into the lungs.
1. It starts when the diaphragm contracts.
2. This leads to increased volume of thoracic chamber.
3. After which the intercostal muscles contracts and leads to the pulling of ribs and sternum which also increases the volume of the thoracic chamber.
4. Now, the increased volume of thoracic chamber also increases the pulmonary volume.
5. This increased pulmonary volume decreases the intra pulmonary pressure less than the atmospheric pressure.
6. Which further causes the entry of external air or oxygen into the lungs also known as inspiration.
Expiration:
1. It starts when the diaphragm relaxes.
2.This leads to decreased volume of thoracic chamber.
3.After which the intercostal muscles relaxes and leads to the relaxation of ribs and sternum which also decreases the volume of the thoracic chamber.
4.Now, the decreased volume of thoracic chamber also decreases the pulmonary volume.
5. This decreased pulmonary volume increases the intra pulmonary pressure less than the atmospheric pressure.
6.Which further causes the exit of external air or carbon dioxide into the atmosphere also known as expiration.
Explain the role of neural system in regulation of respiration.
There are various centres in the neural system that plays significant a role in the regulation and control of respiration.Such centres include:
1.Pneumotaxic centre:
It is present in the dorsal part (back) of the pons varoli of the brain.
Function:This centre decreases the duration of inspiration hence alter the respiration rate.
2. Respiratory Rhythm centre orMedullary inspiratory centre:
It is present in the medulla of the brain.
Function:It regulates the respiratory rhythm.
3. Apneustic centre:It is present in the lower part of the pons varoli of the brain.
Function:It increases the duration of inspiration.
4. Chemosensitive centre:Present in the medulla oblongata and the pons area of the brain.
Function:This area is highly sensitive to carbon dioxide and hydrogen ions.This area starts eliminating these ions when their level is increased.Receptors present in the carotid artery and aortic arch also recognises the difference in carbon dioxide and hydrogen ion concentration.Which thereby send signals to rhythm centre.