Complete the following statements by filling in the blanks.
(1) 21 ÷ 7 … ∵ 21 = 7 × 3
(2) 45 ÷ 15 = …. ∵ 45 …… × ……
(3) We continue to carry out division until we get remainder zero or a whole number less than the ………….
(4) Dividend = division × (….) + (….), 0 ≤ remainder < divisor
(5) When we divide 43 by 5, the quotient is ………… and the remainder is ……….
Here, dividend = ………., divisor = ………
∴ 43 = 5 × …… + ……
(6) 2y × ……… = 10y2
(7) 5x × ……… = 15x4
(8) m2 × ……… = 9m4
(9) 3m × ………… = 9m4+
(1) Here,
21/7
We know that 7 when multiplied by 3, we get 21 as the result.
So when 21 is divided by 7 we get 3 as the quotient.
So the answer is
21÷7 = 3 Q 21 = 7 × 3
(2) Here,
45/15
We know that 15 when multiplied by 3, we get 45 as the result.
So when 45 is divided by 15 we get 3 as the quotient.
So the answer is
45÷15 = 3 Q 45 = 15 × 3
(3) We continue to carry out division until we get remainder zero or a whole number less than the divisor.
(4) The above relation is as follows:
Dividend = Divisor × Quotient + Remainder
The number which we divide is called the dividend and the number by which we divide is called as divisor.
The result obtained is called as quotient and the number leftover is called as the remainder.
(5) For any number to be perfectly divisible by 5, the number should end by 5 or zero.
So 43 is not perfectly divisible by 5.
When we divide 43 by 5, the quotient is 8 and the remainder is 3.
When we divide 43 by 5, the quotient is 8 and the remainder is 3
Here, dividend = 43, divisor = 5
43 = 5 × 8 + 3
(6) For the polynomial 2y,
When 2y is multiplied 5y,
2× 5 = 10 and y × y = y2
So,
2y × 5y = 10 y2
(7) For the polynomial 5x,
When 5x is multiplied 3x3,
3 × 5 = 15 and x3 × x = x4
So,
5x × 3x3 = 15 x4
(8) For the polynomial m2,
When m2 is multiplied 9 m2,
1 × 9 = 9 and m2 × m2 = m4
So,
m2 × 9 m2 = 9 m4
(9) For the polynomial 3m,
When 3m is multiplied 3 m3,
3 × 3 = 9 and m3 × m = m4
So,
3m × 3 m3 = 9 m4
Divide the first polynomial by the second. Explain the steps.
21b; 4
The division is as follows:
Here when 7 is multiplied by 3b we get 21b as the result.
In division the sign of the product [divisor × quotient] is always inverted to get the final result.
So the sign of product should always be opposite to that of the dividend.
So 21b becomes perfectly divisible by 7 and hence the quotient is 3b and remainder is 0.
Divide the first polynomial by the second. Explain the steps.
36p2; 6p
The division is as follows:
Here when 6p is multiplied by 6p we get 36p2 as the result.
In division the sign of the product [divisor × quotient] is always inverted to get the final result.
So the sign of product should always be opposite to that of the dividend.
So 36p2 becomes perfectly divisible by 6p and hence the quotient is 6p and remainder is 0.
Divide the first polynomial by the second. Explain the steps.
5a3; a3
The division is as follows:
Here when a3 is multiplied by 5 we get 5a3 as the result.
In division the sign of the product [divisor × quotient] is always inverted to get the final result.
So the sign of product should always be opposite to that of the dividend.
So 5a3 becomes perfectly divisible by a3 and hence the quotient is 5 and remainder is 0.
Divide the first polynomial by the second. Explain the steps.
–30n2; 3n
The division is as follows:
Here when 3n is multiplied by -10n we get -30n2 as the result.
Here the dividend is negative so the quotient has to be negative to get remainder zero.
In division the sign of the product [divisor × quotient] is always inverted to get the final result.
So the sign of product should always be opposite to that of the dividend.
So -30n2 becomes perfectly divisible by 3n and hence the quotient is -10n and remainder is 0.
Divide the first polynomial by the second. Explain the steps.
15m3; 5m
The division is as follows:
Here when 5m is multiplied by 3m2 we get 15m3 as the result.
In division the sign of the product [divisor × quotient] is always inverted to get the final result.
So the sign of product should always be opposite to that of the dividend.
So 15m3 becomes perfectly divisible by 5m and hence the quotient is 3m2 and remainder is 0.
Divide the first polynomial by the second. Explain the steps.
2b5; b2
The division is as follows:
Here when b2 is multiplied by 2b3 we get 2b5 as the result.
In division the sign of the product [divisor × quotient] is always inverted to get the final result.
So the sign of product should always be opposite to that of the dividend.
So 2b5 becomes perfectly divisible by b2 and hence the quotient is 2b3 and remainder is 0.
Divide the first polynomial by the second. Explain the steps.
78x4; –7x2
The division is as follows:
Here when -7x2 is multiplied by -4x2 we get -28x4 as the result.
Here the divisor is negative so the quotient has to be negative to get remainder zero.
In division the sign of the product [divisor × quotient] is always inverted to get the final result.
So the sign of product should always be opposite to that of the dividend.
So -28x4 becomes perfectly divisible by -7x2 and hence the quotient is -4x2 and remainder is 0.
Divide the first polynomial by the second. Explain the steps.
–8y5; –y3
The division is as follows:
Here when –y3 is multiplied by 8y2 we get -8y5 as the result.
Here the divisor is negative and the dividend is also negative so the quotient has to be positive to get remainder zero.
In division the sign of the product [divisor × quotient] is always inverted to get the final result.
So the sign of product should always be opposite to that of the dividend.
So -8y5 becomes perfectly divisible by –y3and hence the quotient is 8y2 and remainder is 0.
Divide.
4n4 ÷ n2
The division is as follows:
Here when n2 is multiplied by 4n2 we get 4n4 as the result.
In division the sign of the product [divisor × quotient] is always inverted to get the final result.
So the sign of product should always be opposite to that of the dividend.
So 4n4 becomes perfectly divisible by n2 and hence the quotient is 4n2 and remainder is 0.
Divide.
52m3 ÷ 13m
The division is as follows:
Here when 13m is multiplied by 4m2 we get 52m3 as the result.
In division the sign of the product [divisor × quotient] is always inverted to get the final result.
So the sign of product should always be opposite to that of the dividend.
So 52m3 becomes perfectly divisible by 13m and hence the quotient is 4m2 and remainder is 0.
Divide.
20c2 ÷ 15c
The division is as follows:
Here when 15c is multiplied by 1c we get 15c2 as the result.
In division the sign of the product [divisor × quotient] is always inverted to get the final result.
So the sign of product should always be opposite to that of the dividend.
So 20c2 when divided by 15c, the quotient is 1c and remainder is 5c2.
Divide.
36x5 ÷ 4x3
The division is as follows:
Here when 4x3 is multiplied by 9x2 we get 36x5 as the result.
In division the sign of the product [divisor × quotient] is always inverted to get the final result.
So the sign of product should always be opposite to that of the dividend.
So 36x5 becomes perfectly divisible by 4x3 and hence the quotient is 9x2 and remainder is 0.
Divide.
40a2 ÷ (–10a)
The division is as follows:
Here when -10a is multiplied by -4a we get 40a2 as the result.
Here the divisor is negative so the quotient has to be negative to get remainder zero.
In division the sign of the product [divisor × quotient] is always inverted to get the final result.
So the sign of product should always be opposite to that of the dividend.
So 40a2 becomes perfectly divisible by -10a and hence the quotient is -4a and remainder is 0.
Divide.
(–33y4) ÷ (–11y)
The division is as follows:
Here when –11y is multiplied by 3y3 we get -33y4 as the result.
Here the divisor is negative and the dividend is also negative so the quotient has to be positive to get remainder zero.
In division the sign of the product [divisor × quotient] is always inverted to get the final result.
So the sign of product should always be opposite to that of the dividend.
So -33y4 becomes perfectly divisible by -11y and hence the quotient is 3y3 and remainder is 0.
Write five different pairs of dividends and divisors such that the quotient in each case is 2x.
To get quotient as 2x,
Let us use the dividend, divisor and quotient rule.
Dividend = Divisor × Quotient + Remainder
Here,
Remainder = 0
Quotient = 2x
1st Dividend, Divisor:
Let Divisor = 5x
∴ Dividend = 5x × 2x = 10x2
2nd Dividend, Divisor:
Let Divisor = 6x2
∴ Dividend = 6x2 × 2x = 12x3
3rd Dividend, Divisor:
Let Divisor = 7x3
∴ Dividend = 7x3 × 2x = 14x4
4th Dividend, Divisor:
Let Divisor = 8x
∴ Dividend = 8x × 2x = 16x2
5th Dividend, Divisor:
Let Divisor = 6x5
∴ Dividend = 6x5 × 2x = 12x6
Fill in the blanks in the division shown below.
Quotient: …………….; Remainder: ………….
()
Quotient :
Remainder : 0
Here, the divisor is , dividend is
Dividend=(Divisor x Quotient)+(Remainder)
=
Divide the binomial by the monomial. Write the quotient and the remainder.
Quotient: n
Remainder: 3
Divide the binomial by the monomial. Write the quotient and the remainder.
Quotient: p
Remainder: -6
Divide the binomial by the monomial. Write the quotient and the remainder.
Quotient: x-5
Remainder: 0
Divide the binomial by the monomial. Write the quotient and the remainder.
Quotient: 2y+5
Remainder: 0
Divide the binomial by the monomial. Write the quotient and the remainder.
Quotient: 4a-6
Remainder: 0
Divide the binomial by the monomial. Write the quotient and the remainder.
Quotient:
Remainder: 0
Divide the binomial by the monomial. Write the quotient and the remainder.
Quotient:
Remainder: 0
Divide the binomial by the monomial. Write the quotient and the remainder.
Quotient:
Remainder: 0
Divide.
Quotient:
Remainder: 0
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Quotient:
Remainder: 0
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Quotient:
Remainder: 0
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Quotient:
Remainder: 0
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Quotient:
Remainder: 0
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Quotient:
Remainder: 0
Divide.
Quotient:
Remainder: 0
Divide.
Quotient:
Remainder: 0
Divide. Write the answer in the form ‘Dividend = divisor × quotient + remainder’.
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide. Write the answer in the form ‘Dividend = divisor × quotient + remainder’.
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide. Write the answer in the form ‘Dividend = divisor × quotient + remainder’.
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide. Write the answer in the form ‘Dividend = divisor × quotient + remainder’.
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide. Write the answer in the form ‘Dividend = divisor × quotient + remainder’.
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide. Write the answer in the form ‘Dividend = divisor × quotient + remainder’.
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide. Write the answer in the form ‘Dividend = divisor × quotient + remainder’.
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide. Write the answer in the form ‘Dividend = divisor × quotient + remainder’.
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide. Write the quotient and remainder.
Quotient:
Remainder: 0
Divide. Write the quotient and remainder.
Quotient:
Remainder: 8
Divide. Write the quotient and remainder.
Quotient:
Remainder: 10
Divide. Write the quotient and remainder.
Quotient:
Remainder: 13
Divide. Write the quotient and remainder.
Quotient:
Remainder:
Divide. Write the quotient and remainder.
Quotient:
Remainder: 6
Divide the trinomial by the monomial. Write the answer in the form, ‘Dividend = divisor × quotient + remainder’.
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide the trinomial by the monomial. Write the answer in the form, ‘Dividend = divisor × quotient + remainder’.
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide the polynomial by the binomial. Write your answer in the form: Divided = divisor × quotient + remainder
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide the polynomial by the binomial. Write your answer in the form: Divided = divisor × quotient + remainder
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide the polynomial by the binomial. Write your answer in the form: Divided = divisor × quotient + remainder
The dividend can be rewritten as
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide the polynomial by the binomial. Write your answer in the form: Divided = divisor × quotient + remainder
The dividend can be rewritten as
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide the polynomial by the binomial. Write your answer in the form: Divided = divisor × quotient + remainder
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide the polynomial by the binomial. Write your answer in the form: Divided = divisor × quotient + remainder
The dividend can be rewritten as
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide the polynomial by the binomial. Write your answer in the form: Divided = divisor × quotient + remainder
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide the polynomial by the binomial. Write your answer in the form: Divided = divisor × quotient + remainder
The dividend can be rewritten as
Dividend:
Divisor:
Quotient:
Remainder:
‘Dividend = divisor × quotient + remainder’.
Divide the polynomial by each of the following binomials. Write the quotient and remainder.
Quotient:
Remainder: 0
Divide the polynomial by each of the following binomials. Write the quotient and remainder.
Quotient:
Remainder: 0
Divide the polynomial by each of the following binomials. Write the quotient and remainder.
Quotient:Remainder: 0
Divide the polynomial by each of the following binomials. Write the quotient and remainder.
Quotient:Remainder: 240
Divide the polynomial by each of the following binomials. Write the quotient and remainder.
Quotient:Remainder: 0